Electronvolts (eV) to Foot-pounds (ft-lbf) conversion

1 eV = 1.181705e-19 ft-lbfft-lbfeV
Formula
1 eV = 1.181705e-19 ft-lbf

Understanding Electronvolts to Foot-pounds Conversion

An electronvolt (eV) is a unit of energy of about 1.602 × 10⁻¹⁹ joules, used to describe the energies of electrons, photons, and subatomic particles. A foot-pound (ft·lbf) is an imperial unit of mechanical energy equal to the work of one pound-force acting through one foot, about 1.35582 joules. Converting electronvolts to foot-pounds contrasts the minuscule energy of a single particle with a familiar unit of mechanical work.

Conversion Formula

1 eV=1.18171×1019 ft-lbf1\ \text{eV} = 1.18171 \times 10⁻¹⁹\ \text{ft-lbf}

To convert Electronvolts to Foot-pounds, multiply by this factor:

ft-lbf=eV×1.181705×1019\text{ft-lbf} = \text{eV} \times 1.181705 \times 10⁻¹⁹

Step-by-Step Example

Convert 25 Electronvolts to Foot-pounds.

ft-lbf=25×1.181705×1019=2.95426×1018 ft-lbf\text{ft-lbf} = 25 \times 1.181705 \times 10⁻¹⁹ = 2.95426 \times 10⁻¹⁸\ \text{ft-lbf}

How to Convert Electronvolts to Foot-pounds

Use the ratio between the electronvolt and the imperial foot-pound of energy.

  1. Note the factor: One electronvolt equals 1.181705×10191.181705 \times 10⁻¹⁹ foot-pounds.
  2. Take your value: Start with the energy in electronvolts.
  3. Multiply: Multiply the electronvolt figure by 1.181705×10191.181705 \times 10⁻¹⁹, keeping scientific notation.
  4. Result: For 25 eV, the result is 25×1.181705×1019=2.95426×101825 \times 1.181705 \times 10⁻¹⁹ = 2.95426 \times 10⁻¹⁸ ft-lbf.

Electronvolts to Foot-pounds conversion table

Electronvolts (eV)Foot-pounds (ft-lbf)
00
11.181705e-19
22.36341e-19
33.545115e-19
44.726819e-19
55.908524e-19
67.090229e-19
78.271934e-19
89.453639e-19
91.063534e-18
101.181705e-18
151.772557e-18
202.36341e-18
252.954262e-18
303.545115e-18
404.726819e-18
505.908524e-18
607.090229e-18
708.271934e-18
809.453639e-18
901.063534e-17
1001.181705e-17
1501.772557e-17
2002.36341e-17
2502.954262e-17
3003.545115e-17
4004.726819e-17
5005.908524e-17
6007.090229e-17
7008.271934e-17
8009.453639e-17
9001.063534e-16
10001.181705e-16
20002.36341e-16
30003.545115e-16
40004.726819e-16
50005.908524e-16
100001.181705e-15
250002.954262e-15
500005.908524e-15
1000001.181705e-14
2500002.954262e-14
5000005.908524e-14
10000001.181705e-13

What is the Electronvolt?

The electronvolt is a small unit of energy used throughout atomic, nuclear, and particle physics to describe the energies of individual particles, photons, and chemical or nuclear reactions.

Definition

One electronvolt is the kinetic energy gained by a single electron accelerated through an electric potential difference of one volt:

1 eV=1.60218×1019 J1\ \text{eV} = 1.60218 \times 10⁻¹⁹\ \text{J}

Since the 2019 redefinition of SI units, this value is exact: 1 eV = 1.602176634 × 10⁻¹⁹ J, because the elementary charge is now a defined constant. Common multiples include the keV (10³ eV), MeV (10⁶ eV), GeV (10⁹ eV), and TeV (10¹² eV).

Origin and History

The unit arose in the early 20th century as physicists studied electrons and ions accelerated in vacuum tubes and early particle accelerators, where energy expressed in volts of accelerating potential was far more natural than joules. It became the standard energy scale as quantum and nuclear physics matured.

Law and Notable Facts

The electronvolt is accepted for use with the SI system though it is not itself an SI unit. Via mass-energy equivalence, particle masses are routinely quoted in eV/c²: the electron's rest mass is about 511 keV/c², and the proton's is about 938 MeV/c².

Real-World Examples and Conversions

  • Visible-light photons carry roughly 1.6 to 3.3 eV each.
  • Chemical bond energies are typically a few eV per bond.
  • The Large Hadron Collider accelerates protons to about 6.5 TeV, or 6.5 × 10¹² eV, roughly 1.04 microjoules per proton.

What is the Foot-pound?

The foot-pound (foot-pound-force) is a unit of energy or work in the imperial and US customary systems, representing mechanical work done against gravity or by a force.

Definition

One foot-pound is the work done when a force of one pound-force moves an object one foot in the direction of the force:

1 ft-lbf=1.35582 J1\ \text{ft-lbf} = 1.35582\ \text{J}

Precisely, 1 ft·lbf = 1.3558179483314004 J, derived from the standard pound-force (4.4482216152605 N) times the international foot (0.3048 m). It should not be confused with the pound-foot, the identical-magnitude unit conventionally reserved for torque.

Origin and History

The unit grew directly out of imperial mechanics, combining the foot and the pound-force, the everyday units of length and weight in Britain and America. It became a standard measure of work in engineering and firearms ballistics long before metric energy units gained ground in the English-speaking world.

Law and Notable Facts

The foot-pound remains widely used in the United States, especially for muzzle energy of firearms and for engine and tool work ratings. Multiplying foot-pounds per unit time gives power; 550 ft·lbf per second defines one mechanical horsepower.

Real-World Examples and Conversions

  • 1 foot-pound is about 1.356 joules.
  • A .22 Long Rifle bullet typically leaves the muzzle with roughly 100 to 140 ft·lbf of energy.
  • Lifting a 50-pound weight by 4 feet requires 200 ft·lbf, or about 271 joules of work.

Frequently Asked Questions

How many foot-pounds are in one electronvolt?

One electronvolt equals about 1.181705×10191.181705 \times 10⁻¹⁹ foot-pounds, a negligible amount of mechanical work.

How do I convert electronvolts to foot-pounds?

Multiply the electronvolt value by 1.181705×10191.181705 \times 10⁻¹⁹ and express the result in scientific notation.

How many electronvolts make one foot-pound?

One foot-pound contains about 8.46235×10188.46235 \times 10¹⁸ electronvolts, a vast number reflecting the scale difference.

Why compare electronvolts to foot-pounds?

Such comparisons highlight scale in physics education, showing that even trillions of particle energies amount to only a small everyday mechanical work value.

What is a foot-pound of energy?

A foot-pound is the work done when a force of one pound-force moves an object one foot along its line of action, equal to about 1.35582 joules.

Complete Electronvolts conversion table

eV
UnitResult
Watt-seconds (Ws)1.602177e-19 Ws
Watt-minutes (Wm)2.670294e-21 Wm
Watt-hours (Wh)4.450491e-23 Wh
Milliwatt-hours (mWh)4.450491e-20 mWh
Kilowatt-hours (kWh)4.450491e-26 kWh
Megawatt-hours (MWh)4.450491e-29 MWh
Gigawatt-hours (GWh)4.450491e-32 GWh
Joules (J)1.602177e-19 J
Kilojoules (kJ)1.602177e-22 kJ
Megajoules (MJ)1.602177e-25 MJ
Gigajoules (GJ)1.602177e-28 GJ
British Thermal Units (IT) (BTU)1.51857e-22 BTU
US Therms (thm)1.518933e-27 thm
Ergs (erg)1.602177e-12 erg
Foot-pounds (ft-lbf)1.181705e-19 ft-lbf
Tonnes of TNT (t-tnt)3.829294e-29 t-tnt
calories (cal)3.829294e-20 cal
Kilocalories (kcal)3.829294e-23 kcal